Q:

Which expression completes the statement to form a true inequality?3+62<3³ + 125² + 4²2³ + 5² + 62³ + 14 + 17

Accepted Solution

A:
we are supposed to find The expression that completes the statement to form a true inequality[tex] 3+6^2<......\\ [/tex]Here [tex] 3+6^2=3+36=39\\ [/tex]So the given inequality to be true the value of the option(s) should me bore than 39First option: [tex] 3^3 + 12=27+12=39 [/tex]As its not more than 39. Hence its not the correct option.Second Option : [tex] 5^2 + 4^2=25+16=41\\ [/tex]Hence this is the correct option so,[tex] 3+6^2<5^2 + 4^2\\ [/tex]Third Option: [tex] 2^3 + 5^2 + 6=8+25+6=39\\ [/tex]As its not more than 39. Hence its not the correct option.Fourth Option: [tex] 2^3 + 14 +17=8+ 14 +17=39\\ [/tex]As its not more than 39. Hence its not the correct option.